3x(4x+2)=2(6x^2+3x)

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Solution for 3x(4x+2)=2(6x^2+3x) equation:


Simplifying
3x(4x + 2) = 2(6x2 + 3x)

Reorder the terms:
3x(2 + 4x) = 2(6x2 + 3x)
(2 * 3x + 4x * 3x) = 2(6x2 + 3x)
(6x + 12x2) = 2(6x2 + 3x)

Reorder the terms:
6x + 12x2 = 2(3x + 6x2)
6x + 12x2 = (3x * 2 + 6x2 * 2)
6x + 12x2 = (6x + 12x2)

Add '-6x' to each side of the equation.
6x + -6x + 12x2 = 6x + -6x + 12x2

Combine like terms: 6x + -6x = 0
0 + 12x2 = 6x + -6x + 12x2
12x2 = 6x + -6x + 12x2

Combine like terms: 6x + -6x = 0
12x2 = 0 + 12x2
12x2 = 12x2

Add '-12x2' to each side of the equation.
12x2 + -12x2 = 12x2 + -12x2

Combine like terms: 12x2 + -12x2 = 0
0 = 12x2 + -12x2

Combine like terms: 12x2 + -12x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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